Use preceding-sibling to find all unique elements

Recently I need to write a xpath expression to find all unique elements from one XML message.  The below is the simplified XML document that demonstrate the problem to be solved.  Here I want to get a list of all unique of all a elements.  The of values in the result list should be 123, 120, 129,345 and 340.

<?xml version="1.0" encoding="UTF-8"?>
 
<!--Sample XML file generated by XMLSpy v2008 sp1 (http://www.altova.com)-->
 
<db:p>
 
 <db:ss>
 
  <db:tt>
 
   <db:a>123</db:a>
 
   <db:a>120</db:a>
 
  </db:tt>
 
  <db:tt>
 
   <db:a>123</db:a>
 
   <db:a>129</db:a>
 
  </db:tt>
 
 </db:ss>
 
 <db:ss>
 
  <db:tt>
 
   <db:a>345</db:a>
 
   <db:a>120</db:a>
 
   <db:a>123</db:a>
 
   <db:a>340</db:a>
 
  </db:tt>
 
 </db:ss>
 
</db:p>
 

After some tries I come out with the following xpath expression.

/*:p/*:ss/*:tt/*:a[ not(. = ../preceding-sibling::*/*:a)  and not(. =  ../../preceding-sibling::*/*:tt/*:a)]

Here I use two preceding-sibling because <a> element is under <ss> and <tt> elements.